Math, asked by tn33626010113, 10 months ago

A lab technician has one solution that is
60% chlorinated and another that is 40%
chlorinated. How much litres of 40%
chlorinated solution is needed to make a
100 litres solution that is 50% chlorine?
50 litres
54 litres
40 litres
48 litres​

Answers

Answered by koushikreddy2004
0

a lab technician has one solution that is 60% chlorinated and another that is 40% chlorinated. how much of each solution is needed to make a 100 L solution that is 50% clorine?

---------------------

60% solution DATA:

Amount is "x" L ; amount of chlorine in them is 0.6x L

------------------- --

40% solution DATA:

Amount is "100-x" L ; amount of chlorine in them is 0.4(100-x)=(40-0.4x) L

------------------ ---

Mixture DATA:

Amount is 100 L ; amount of chlorine is 0.5(100)= 50 L

----------------- -----

EQUATION:

chlorine + chlorine = chlorine

0.6x + 40-0.4x = 50

0.3x=10

x=33.3 L (amount of 60% solution in the mixture)

100-33.3 L = 66.7 L (amount of 40% solution in the mixture)

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Answered by tharunichinni30
0

Answer:

Step-by-step explanation:

60% solution DATA:

Amount is "x" L ; amount of chlorine in them is 0.6x L

-------------------

40% solution DATA:

Amount is "100-x" L ; amount of chlorine in them is 0.4(100-x)=(40-0.4x) L

------------------

Mixture DATA:

 

Amount is 100 L ; amount of chlorine is 0.5(100)= 50 L

-----------------

EQUATION:

chlorine + chlorine = chlorine

0.6x + 40-0.4x = 50

0.3x=10

x=33.3 L (amount of 60% solution in the mixture)

100-33.3 L = 66.7 L (amount of 40% solution in the mixture)

hope uh got this answer

and please mark my answer as brainlist

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