Math, asked by polinakrumkachev, 2 months ago

a lab technician mixes a 10% acid solution with a 50% acid solution to create 40 mL of a 40% solution how much of each solution must be used????

Answers

Answered by kanishkagupta1234
8

Answer:

u = volume of the 10% solution

v = volume of the 50% solution

%2810u%2B50v%29%2F%28400%29=40 and u%2Bv=400

Solve for u and v.

First simplify the rational equation:

10%28u%2B5v%29=16000

highlight_green%28u%2B5v=1600%29

Next, for convenience, subtract the "400" equation from this simplified "1600" equation and solve for v; and then use either equation to finish solving for the value of u.

Answered by llMissSwagll
6

 \huge \sf \underline \pink{answer}

u = volume of the 10% solution

v = volume of the 50% solution

 and 

Solve for u and v.

First simplify the rational equation:

Next, for convenience, subtract the "400" equation from this simplified "1600" equation and solve for v; and then use either equation to finish solving for the value of u.

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