Question

A laboratory procedure calls for making 600.0mL of a 1.1M KNO3 solution. How much KNO3 in grams is needed?

Answer 1

Answer:

if you only need 1.1 M and not 1.10 M or 1.100 M, you can go for 66.73 g and still be quite close.

Explanation:

1.1M of soln means 1.1 no. of moles dissolved in 1L of soln

M=molL

   MK=39.098 g/mol

   MN=14.007 g/mol

   MO=15.999 g/mol

   MKNO3=39.098+14.007+3⋅15.999=101.102 g/mol

   1.1mol

L⋅1L1000mL⋅600.0mL⋅101.102gmol

= 66.72732 g