Question

A laboratory test tube in the shape of a right circular cylinder surmounted on a hemisphere of diameter 7cm. If the total height of the test tube is 10.5cm, calculate the capacity of the vessel to the nearest $cm^{3}$

Answer 1

The capacity of the test tube is 358.8 cm³

Step-by-step explanation:

A laboratory test tube in the shape of a right circular cylinder surmounted on a hemisphere

diameter of the tube = 7 cm

radius of the tube = 3.5 cm

total height of the tube= 10.5 cm

radius of hemisphere = height of the hemisphere = 3.5 cm

then height of the cylindrical part = 10.5 - 3.5 = 7 cm

then

capacity of the tube = volume of cylinder + volume of hemisphere

capacity of the tube = $\pi r^2h + \frac{2}{3} \pi r^3$

= $(\frac{22}{7 } \times 3.5\times 3.5 \times 7 )+ (\frac{2}{3}\times \frac{22}{7}\times 3.5\times 3.5\times 3.5 )$

= 269.5 + 89.3

= 358.8 cm³

hence ,

The capacity of the test tube is 358.8 cm³

#Learn more:

A test tube has diameter 20mm and height 15cm the lower portation is hemisphere then capacity of test tube is:

https://brainly.in/question/2693815

Answer 2

Refer to the attachment