Question

A labour dug a well upto a depth of 11 metre. Labour charge Rs. 10 for first
metre and Rs. 45 for each subsequent metres. What should be the amount to be
paid to the labour ?​

Answer 1

Answer:

460 rupees is the answer

Answer 2

Explanation:

Depth up to which the well has to be dug out = 10$$ meters

Charges for first meter = Rs. 200

And there after the price increases by Rs. 50

So, the increase in the price will form an A.P. :200,250,300,.... and the common difference will be 50

Here, n=10 ( depth up to which the well is to be dug out)

Sum of an A.P is given by =

2

n

(2a+(n−1)d)

⇒ labour charge=

2

10

(400+(10−1)×50)

⇒ labour charge=5×850=4250

Now, we need to find the charge for the 10

th

meter or the last term of the resulting A.P.

Sum=

2

n

(a+l)

⇒4250=

2

10

×(200+l)

⇒l=650

Hence, labor charges is require for digging 10

th

meter