Math, asked by jitendrabharpoda, 11 months ago

A labourer was engaged for 30 days on the condition that will get rupees 50 for each day he work and will be fined rupees 10 for each day he is absent if he gets rupees 1200 at the end of the month for how many days did he remain absent

Answers

Answered by eshu001
2

Answer:

Hey mate

Step-by-step explanation:

Your Answer...

⇒ Let number of days labourer did work =xdays

⇒ Then number of days he was absent =(30−x)days

⇒ Amount for days he worked =60x

⇒ Amount cut for days he was absent =10(30−x)=300−10x

According to the question,

60x−(300−10x)=1700

60x−300+10x=1700

50x−300=1700

50x=1400

x=

50

1400

∴ x=28days

⇒ Absent days =30−28=2days

∴ A labourer remain absent for 2days

Thankuu mark as brainliest..

Answered by vasuagarwal110
2

Answer:

30days

Step-by-step explanation:

here

let the days he remain absent be x

so,

30*50-10x=1200

1500-10x=1200

~ 1500-1200=10x

~300=10x

~x=30days

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