A labourer was hired for a month 30 days on the condition that he will receive rupees 60 each day he works and will be find rupees 10 each day he is absent at the end of the month he received rupees 1380 how many days did he work
Answers
Answered by
167
suppose he was present for = x days
then absent for = 30-x days
now equation would be
x (60) - (30-x)(10) = 1380
60x - 300 + 10x = 1380
70x = 1380+300 = 1680
x = 1680/70 = 24
Thus he was at work for 24 days.
then absent for = 30-x days
now equation would be
x (60) - (30-x)(10) = 1380
60x - 300 + 10x = 1380
70x = 1380+300 = 1680
x = 1680/70 = 24
Thus he was at work for 24 days.
Answered by
3
The laborer worked for a total of 24 days in the month.
Given:
Number of days for which the laborer is hired = 30
Amount received for working 1 day = Rs 60
Amount deducted for being absent each day = Rs 10
Total amount received by the laborer at the end of the day = Rs 1380
To Find:
The number of days that the laborer works
Solution:
Let the number of days the laborer works be x
Thus, the number of days he is absent = (30 - x)
Now, we can form the following equation-
60x - 10(30 - x) = 1380
60x - 300 + 10x = 1380
70x - 300 = 1380
70x = 1680
x = 1680/70
x = 24
Thus, the number of days the laborer worked is 24.
#SPJ6
Similar questions