Question

a labourer was hired to complete a certain work in 3 days he completes 38 of the work on the first day and 25 of the work on the second what fraction of work needs to be done on the third day in order to finish the work​

Answer 1

Answer:

Case 1 = 37 %

Case 2 = 46.5 %

Step-by-step explanation:

CASE 1 (we consider the work as the whole work)

The work done on first day = 38 % of whole work

The work done on second day = 25 % of whole work

Let we need x % work

Then we know that

         100 % work = x % + 25 % +38 %

⇒                    x % = 100 - 25 - 38 =  37%

So                   x % = 37 %

Thus we need more 37 % to be done on third day.

CASE 2 ( We consider the remaining work as the whole work)

On first day work have to done work = 100%

works done the work = 38%

So

Remaining work = 100 - 38 = 62 %

Work on second day = 25 % of remaining work = 25 % of 62 % =15.5 %

So remaining work = 62 % - 15.5 % = 46.5 %

Thus

Work need to do 46.5 % on third day