• A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall.
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Answer:
6 metres
Step-by-step explanation:
In ⊥ΔACB, ∠C=90°
Given: AC = 8m, AB = 10 m
To find: BC
Using pythagoras theorem,
(AB)² = (AC)² + (BC)²
(10)² = (8)² + (BC)²
100 = 64 + (BC)²
(BC)² = 100 -64
(BC)² = 36
BC = √36
BC = 6
∴ Ladder is at a distance of 6m from the base of the wall.
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