Question

A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of ladder from the base of the wall

Answer 1

Given figure will form right angled triangle, in which

Hyp =10

Perpendicular =8

Base=?

On using Pythagoras theorem

(Hyp)^2=(perp)^2+(base)^2

100=64+(base)^2

36=(base)^2

Base =6 m

Distance of foot of ladder from the wall is 6 m

Answer 2

Plz refers to the attachments

Given:

A ladder 10 m long reaches a window 8 m above the ground.

To find out:

Find the distance of the foot of ladder from the base of the wall ?

Solution:

Let AB be the ladder, B be the window and CB be the wall.

Then, ABC is a right triangle, right angled at C .

Therefore,

AB² = AC² + BC² ( By pythagoras therome )

⇒ 10² = AC² + 8²

⇒ 100 = AC² + 64

⇒ AC² = 100 - 64

⇒ AC² = 36

⇒ AC = 6 m

Hence the foot of the ladder is at a distance of 6 m from the base of the wall.