Question

A ladder 10 m long reaches a window 8 m above the ground. The distance of the foot of the ladder from the base of the wall is ?​

Answer 1

Step-by-step explanation:

Applying "Pythagoras Property"

please mark as brainliest and follow...

THANKS....

Answer 2

✬ Distance = 6 m ✬

Step-by-step explanation:

Given:

• Length of ladder is 10 m.
• Length of window is 8 m.

To Find:

• Distance of foot of ladder from base of wall ?

Solution: Let AC be a ladder , AB be a window and BC be the distance of between foot of ladder and base of wall.

Now in right angled triangle we have

• AB = perpendicular (8 m)
• AC = hypotenuse (10 m)
• BC = base
• ∠B = 90°

Applying Pythagoras Theorem in ∆ABC

★ H² = Perpendicular² + Base² ★

$\implies{\rm }$ 10² = 8² + b²

$\implies{\rm }$ 10 × 10 = 8 × 8 + b²

$\implies{\rm }$ 100 = 64 + b²

$\implies{\rm }$ 100 – 64 = b²

$\implies{\rm }$ 36 = b²

$\implies{\rm }$ √36 = b

$\implies{\rm }$ √6 × 6 = b

$\implies{\rm }$ 6 = b

Hence, the distance between foot of ladder from base of wall is 6 m.