A ladder 10cm long reaches a window 8m above the ground find the distance of the foot of the ladder from the base of the wall
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Step-by-step explanation:
⊥ΔACB,∠C=90
∘
,BC=?
AC
2
+CB
2
=AB
2
(8)
2
+CB
2
=(10)
2
64+CB
2
=100
CB
2
=100−64
CB
2
=36
∴CB=6
∴ Ladder is at a distance of 6m from the base of the wall.
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