A ladder 10m long reaches a window 8m above the ground. Find the distance of the foot of the bladder from base of the wall.
Answers
Given :
- A ladder 10m long reaches a window 8m above the ground.
To Find :
- Distance from foot of the ladder to the base of the wall = ?
Solution :
We have ,
- Length of ladder = 10 m
- Height of wall = 8 m
★ By using Phythagoras theorem :
Pythagorean theorem, states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle :D
- (Hypotenuse)² = (Base)² + (Height)²
Here,
- Hypotenuse = 10 m
- Base = ?
- Height = 8 m
★ Now, plug in the given values in above formula of Phythagoras theorem :
→ (10)² = (Base)² + (8)²
→ 100 = (Base)² + 64
→ 100 - 64 = Base²
→ 36 = Base²
→ Base = √36
→ Base = 6 m
- Hence ,the distance from foot the ladder to the base of the wall is 6 m.
- A ladder 10m long reaches a window 8m above the ground
- The distance of the foot of the ladder from base of the wall
- Let the distance of the foot of the ladder from base of the wall be "x"
The given case will rise a right angled triangle with its height as the height of wall , its hypotenuse would be the length of ladder and its base will work as the distance of the foot of the ladder from base of the wall.
➠
- Hypotenuse = 10 m
- Base = x
- Height = 8 m
⟮ Putting these values in equation ⓵ ⟯
➜ (Hypotenuse)² = (Base)² + (Height)²
➜ (10)² = (x)² + (8)²
➜ 100 = (x)² + 64
➜ 100 - 64 = x²
➜ x² = 36
➜
- x = 6
- x = -6
As length can't be negative hence x = 6
∴ The distance of the foot of the ladder from base of the wall is 6 m
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