Question

A ladder 10m long reaches a window 8m above the ground. Find the distance of the foot of the ladder. ​

Answer 1

Step-by-step explanation:

⊥ΔACB,∠C=90

∘

,BC=?

AC

2

+CB

2

=AB

2

(8)

2

+CB

2

=(10)

2

64+CB

2

=100

CB

2

=100−64

CB

2

=36

∴CB=6

∴ Ladder is at a distance of 6m from the base of the wall.

Answer 2

${\huge{\rm{\underline{\underline{\rm{Question :-}}}}}}$

→ A ladder 10m long reaches a window 8m above the ground. Find the distance of the foot of the ladder. ​

${\huge{\rm{\underline{\underline{\rm{Given :-}}}}}}$

→ AC (Height of window) = 8 m.

(Perpendicular to the base of ground)

→ BC (Length of Ladder) = 10 m.

 (Hypotenuse of the right angle triangle)

${\huge{\rm{\underline{\underline{\rm{To \: Find :-}}}}}}$

→ AB (Distance of the foot of the ladder from the base of the wall)

  or Base of Δ BAC

${\huge{\rm{\underline{\underline{\rm{Solution :-}}}}}}$

So using Pythagoras Theorem

BC  = AC² + AB²

AB² = BC²- AC²  

AB² = 10² - 8² = 100 - 64

AB = 36

AB = √36 = 6

∴ Ladder is at a distance of 6m from the base of the wall.