Question

A ladder 10m long reaches a window 8m above the ground. Find the distance of the foot of the ladder from base of the wall.

Answer 1

10^2 - 8^2
pythogarous theorum
=100-64
=36
=6^2
hence answer is 6

Answer 2

Since it's given that the window is 8m above the ground

=> Height = 8m

It's clear that the wall (on which window is fixed) will be perpendicular to the ground

And length of the ladder is 10m

But it's given that the length reaches the window which is just 8m high.

This means that the ladder is placed slanting.

=> Hypotenuse = Ladder
Height = Window's height
(Refer the attachment)

So by applying Pythagoras Theorem, we can calculate the distance from the foot of ladder to the base of the wall

Pythagoras theorem :-

P² + B² = H²

Where P = Perpendicular (height)
B = base
and H = hypotenuse

So B² = H² - P²

=> B = √(H² - P²)

Now substitute the value of H and P

=> B = √(10² - 8²)

=> B = √(100 - 64)

=> B = √36

=> B = 6m


Your answer = 6m


Hope it helps dear friend ☺️