Question

A ladder 10m long reaches a window 8m above the ground. Find the distance of the foot of ladder from base of the wall?

Answer 1

$<b>Answer:$

Bc=6

Step-by-step Explanation:

=>Let AC be the ladder of length 10 m and AB=8m

In ∆ABC,

=>BC²+AB²=AC²

=>BC²=AC²-AB²

=>BC²= (10)²-(8)²

=>BC²=100-64

=>BC²=36

=>BC=√36

=>BC=6

Answer 2

Height of the ladder=10m (hypotenuse)

Length of the window=8m (perpendicular)

So we need to find the base

(H) ^ =(p)^ + (b) ^

(10*10) = (8*8) + (B)^

100= 64 + (B)^

100 - 64 =(B)^

36 = (B) ^

6m =base (square goes for square root)

So the distance of the foot of the ladder from the base of the wall is 6 m

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