Question

a ladder 10m long reaches a window 8m above the ground. The distance of the foot of the ladder from the bas of the wall is dash m​

Answer 1

given: length of ladder=10m;

height of wall =8m;

to find: distance of the foot

so, right angle at B, we have triangle ABC. such that AC hypotenuse AB perpendicular and BC base... so,

by P.T we have;

BC^= AC^-AB^

BC^=100-64

BC^=36

BC=6M

Answer 2

Answer:

H^2=P^2+B^2

10^2=8^2+B^2

100=64+B^2

B^2=164

B=√164

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