Question

A ladder 10m long reaches a window which is 8m above the ground on one side of the road, keeping its foot at the same point, the ladder is turned to the other side of the road to reach a window 6m high. what is the width of the road?​

Answer 1

The width of street is 8.2 m.

Step-by-step explanation:

We are given that the two buildings are parallel to each other

Refer the attached figure .

So, AB is parallel to ED

Since we are given that a ladder 5.8m long is placed on the street such that its top just reaches the window of a building at the height of 4m

So. AC = EC = 5.8 m

And AB = 4 m.

On turning the ladder over to the other side of the street its top touches the window of the other building at a height of 4.2m.

So, ED = 4.2 m

So, let BC = x and CD = y

We are required to calculate the width of street i.e. x+y

So, in ΔABC , use Pythagorean Theorem

So, in ΔEDC , use Pythagorean Theorem

So, the width of street = x+y = 4.2+4 =8.2 m

Hence the width of street is 8.2 m.