Question

A ladder 10m long rests against a vertical wall. If the foot of the ladder is 6m away from the wall and the ladder just reaches the top of the wall, how high is the wall?

Answer 1

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here is ur answer

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Answer 2

Given,

• Length of ladder = 10m
• Perpendicular distance = 6m

To find,

• Length of the wall

Solution,

A ladder 10m long rests against a vertical wall. If the foot of the ladder is 6m away from the wall and the ladder just reaches the top of the wall, then the wall is 8m high.

We can simply find the height of the wall by using the Pythagoras theorem.

According to Pythagoras theorem,

     (H)² = (B)² + (P)²

The length of the ladder is the hypotenuse of the right-angle triangle and the foot of the ladder is the base, we have to find the perpendicular distance.

  (10)² = (6)² + (P)²

  100 - 36 = (P)²

           64 =  (P)²

              8 = P

∴ The perpndicular distance is 8m.

Hence, A ladder 10m long rests against a vertical wall. If the foot of the ladder is 6m away from the wall and the ladder just reaches the top of the wall, then the wall is 8m high.