A ladder 10m long rests against a vertual well if the foot of ladder is 6m away from the wall and the ladder just reaches the top of the wall how high is the wall
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length of the ladder=10m
the foot of ladder is 6m away from the wall
we to have find how high the ladder reaches the top.
according to Pythagoras theorem
10^2 - 6^2= distance between them
100-36= distance between them
64
=8m
8×8=64
the ladder will reach I'm long
hope it helps and please mark brainliest.
the foot of ladder is 6m away from the wall
we to have find how high the ladder reaches the top.
according to Pythagoras theorem
10^2 - 6^2= distance between them
100-36= distance between them
64
=8m
8×8=64
the ladder will reach I'm long
hope it helps and please mark brainliest.
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