A ladder 13 m long is placed on the ground in such a way that it touches the top of a vertical wall 12 m high.
Find the distance of the foot of the ladder from the bottom of the wall.
Answers
Answered by
1
Answer:
According to pythagoras theorem,
{ab}^{2} = {ac}^{2} + {bc}^{2}ab2=ac2+bc2
13×13=(12×12)+bc^2
bc^2=169-144
bc^2=25
bc=5m
Answered by
1
Answer:
5 m
Step-by-step explanation:
wall - 12m - AC
ladder - 13m - AB
distance between ladder and wall - BC
by Pythagoras theorem,
(AB)² = (BC)² + (AC)²
(BC)² = AB² - AC²
BC = √13² - 12²
= √ 169 - 144
= √ 25
= 5 m
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