a ladder 13 m long reached a window 12 m height from the ground on placing it against a wall at a distance x .find the distance of the foot of the letter from the wall.
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Answer:
Length of ladder =13 m.
BC=12m,AC=13 m.
In ΔABC,
AB2+BC2=C2 (Pythagoras theorem)
AB2=AC2−BC2
=132−122
=169−144
=25
∴AB=5 m.
∴ The distance of the foot of the ladder from the base of the wall =5 m
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Length of ladder =13 m.BC=12m,AC=13 m.In ΔABC,AB 2 +BC 2 =C 2 (Pythagoras theorem)AB 2 =AC 2 −BC 2 =13 2 −12 2 =169−144=25∴AB=5 m.∴ The distance of the foot of the ladder from the base of the wall =5 m
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