Question

A ladder 13 metres long stands at one side of a path, its top touching a wall on
the other side of the path at a height of 12 metres. Find the width of the path.​

Answer 1

Answer:

base is 5 m hope it helps you

Step-by-step explanation:

according to the question we know it is a right angle triangle

Here,

perpendicular Height = 12m

Hypotenuse = 13m

Base = ?

So, by Pythagoras theorem

$Hypotenuse^{2} = height^2 + base^2\\13^2 = 12^2 + base^2\\169 = 144 + base^2\\169-144 = base^2\\25 = base^2\\5 = base$

Answer 2

Answer:

Step-by-step explanation:

Length of ladder =13 m.

BC=12m,AC=13 m.

In ΔABC,

AB  

2

+BC  

2

=C  

2

         (Pythagoras theorem)

AB  

2

=AC  

2

−BC  

2

 

=13  

2

−12  

2

 

=169−144

=25

∴AB=5 m.

∴ The distance of the foot of the ladder from the base of the wall =5 m