Question

A ladder 13m long is kept near a wall. The top of the ladder touches the wall at 12m. Find the distance between the base of the ladder and the wall.

Answer 1

Answer:

Heya,

Length of ladder = 13\ m=13 m.

BC = 12 m, AC = 13\ m.BC=12m,AC=13 m.

In \Delta ABCΔABC,

AB^2 + BC^2 = C^2AB

2

+BC

2

=C

2

(Pythagoras theorem)

AB^2 = AC^2 - BC^2AB

2

=AC

2

−BC

2

= 13^2 - 12^2=13

2

−12

2

= 169 - 144=169−144

= 25=25

\therefore AB = 5\ m.∴AB=5 m.

\therefore∴ The distance of the foot of the ladder from the base of the wall = 5\ m=5 m

solution

Answer 2

Answer:

5 m

Step-by-step explanation:

by pythagoras theorem

h=113

p=12

b2=square of 13 - square of 12

= 169 - 144

b= square root of 25

b=5

hope u understand

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