Question

A ladder 13m long is placed on the ground in such a way that it touches the top of a vertical wall 12m high. find the distance of the foot of the ladder from the bottom of the wall.​

Answer 1

Answer:

Solve with pythagorean theorem

c^2=a^2+b^2

c-measure of the laddee

b-measure of the vertical wall from the top of the ladder to the ground

a-distance of the foot of the ladder to the bottom of the wall.

c=13m

b=12m

a=?

c^2=a^2+b^2

13^2=a^2+12^2

13^2-12^2=a^2

169-144=a^2

√25=√a^2

5 m=a----- final answer

The distance of the foot of the ladder to the bottom of the wall is 5 m high

Step-by-step explanation:

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Answer 2

Answer:

height of ladder = 13m

height of wall = 12 m

it forms a triangle apply Pythagoras theorem

h^2 = p^2+b^2

h^2 = 12^2+13^2

h^2 = 144+169

h^2 = 313

h = √313