Question

A ladder 13m.long reaches a window
of building 12m.above the ground
Determine
the distance of the foot of the ladder
from the building?​

Answer 1

5m

Step-by-step explanation:

Given,

Length of ladder = 13m

Height of ladder from ground = 12m

Distance of foot (BC) = ?

Applying Pythagorean property.

(Refer attachment )

Answer 2

Answer :-

The distance of the foot of the ladder from the building is 5m.

Step-by-step explanation:

FIGURE :-

$\setlength{\unitlength}{1cm}\begin{picture}(6,5)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(1.02,1.02){\framebox(0.3,0.3)}\put(-0.3,2.5){\large\bf 12m}\put(3.6,2.7){\large\bf 13m}\put(.7,4.8){\large\bf A}\put(.8,.3){\large\bf C}\put(5.8,.3){\large\bf B}\end{picture}$

Here,

• AB = 13m
• AC = 12m
• BC = ? [distance between the ladder and the building]

We can find out the distance by applying "Pythagoras theorem"

Therefore,

$\sf{\longrightarrow \: {AB}^{2} = {AC}^{2} + {BC}^{2}}$

$\sf{\longrightarrow \: {13}^{2} = {12}^{2} + {BC}^{2}}$

$\sf{\longrightarrow \: 169 = 144 + {BC}^{2}}$

$\sf{\longrightarrow \: 169 - 144 = {BC}^{2}}$

$\sf{\longrightarrow \: 25 = {BC}^{2}}$

$\sf{\longrightarrow \: {BC}^{2} = 25}$

$\sf{\longrightarrow \: BC = \sqrt{25}}$

$\sf{\longrightarrow \: \underline{BC = 5m}}$

Hence, The distance between the ladder and the building is 5m.