a ladder 13mtrs long is placed on the ground in such a way that it touches the top of a vertical wall 12mtrs high. Find the distance between the foot of the ladder to the bottom of the wall.
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5 I hope it is helpful for you
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Let a right angle ∆abc right angled at b.
So, by using Pythagoras theorem
(AC)^2=(BC)^2+(AB)^2
Let AC=13, BC=K and AB=12
(13)^2=(K)^2+(12)^2
169=k^2+144
169-144=k^2
25=k^2
√25=K
K=5
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