a ladder 15 m long just reaches the top of a vertical wall if the ladder makes an angle of 60 with the wall, find the height of the wall
Answers
Answer:
7.5m
Step-by-step explanation:
Draw the rough diagram which shows the details of the problem
Diagram shows a right angled triangle ABC. Right angle at
Let the length of ladder AC=15m
(hypotenuse)
Angle between ladder and wall < BCA=60°
Height of the wall=BC
From triangle ABC
Sin
Sin 30=BC/15
1/2=BC/15
15/2=BC
7.5=BC
Therefore,
Height of the wall=BC=7.5m
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Given data:-
- A ladder 15m long, just reaches the top of a vertical wall.
- The ladder makes an angle of 60° with the wall.
Assumption:-
- Let, AB be the wall which is perpendicular to the ground. and CA be the ladder of length 15m.{Hence angle ABC = 90°}
- Let, angle CAB is of 60° {according to figure and given}.
Solution:-
According to assumption & figure
—› CA = hypotenuse
To find the height of the wall.
{We need to take, sin ratio with opposite angle of wall}
Hence, we need to find opposite angle of wall. and opposite angle of wall is angle BCA.
To find angle ABC :-
We know, "Sum of all angles of triangle is equal to 180°. hence,
—› angle ABC + angle BCA + angle CAB
= 180
—› 90 + angle BCA + 60 = 180
—› angle BCA + 150 = 180
—› angle BCA = 180 - 150
—› angle BCA = 30°
According to assumption & figure
—› AB = opposite side to angle angle BCA
Now, we use sin ratio with angle BCA, where, θ = 30°
—› Sin( θ ) = {opposite side}/{hypotenuse}
—› Sin( 30 ) = AB/CA
—› 1/2 = AB/15 i.e.
—› AB = 15/2
—› AB = 7.5 m