A ladder 15 m long makes an angle of 60 with the wall. find the height of the point where the ladder touches the wall.
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Let ABC be a right angled triangle, where AC is ladder =15m and angle C=60°
We have to find height of the wall that is AB =?
Therefore; sin60°= AB/AC
=) √3/2=AB/15
=) 15×√3/2 =AB
=) AB = 15√3/2 m ..
Hope it Helps
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We have to find height of the wall that is AB =?
Therefore; sin60°= AB/AC
=) √3/2=AB/15
=) 15×√3/2 =AB
=) AB = 15√3/2 m ..
Hope it Helps
Mark as Brainliest..
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