A ladder 15m long reaches a window which is 9 m above the ground on one side of a street. Keeping its foot at the same point, the ladder is turned to other side of the street to reach a window 12m high. Find the width of the street.
Answers
Answer:
this can be solved using Pythagoras theorem since the length of ladder is 15 m and the window is 12m high (from the ground) ,let the ladder be the hypotenuse and the window be side 1in a right angled triangle
and let street be side 2
therefore by pythagoras theorem
(hypo)^2=(side1)^2+(side2)^2
(15)^2=(12)^2+side 2^2
225=144+ side 2^2
225-144=side2^2
81 =side 2^2
therefore length of side 2=square root of 81 I.e.9
therefore width of street is 9m
similarly using Pythagoras theorem for the first case ,we get the width of street as 12 m
therefore adding both the width of streets
we get
9+12=21 m
therefore 21 m is the total width of the street
hope it works !!:)
Answer:
Step-by-step explanation:
Height of the ladder = 15m (Given)
Height of the window = w1 = 9m (Given)
Height of the window = w2 = 12m (Given)
in Δ ABC by Pythagoras theorem
CA² + AB² = CB²
CA² = 225 - 144
CA² = 81
CA = 9 m
Similarly in ΔCDE by Pythagoras theorem
CD² + DE² = CE²
CE² = 225-81
CE² = 144
CE = 12m
Thus, width of street AB = CA+CE
= 12+9
= 21m