A ladder 17 m long is inclined against a wall 15 feet high. Find how far away the foot of the ladder is from the wall.
Answers
Answer:
From the problem we have given that,
The length of wall = 15m
The length of the ladder = 17m
As the wall and ground makes an angle , here the ladder will act as a hypotenuse.
Therefore here a right-angled triangle is formed.
Now denote the length of wall = AB=15m
Also the length of ladder = AC =17m
And the distance between the foot of ladder to the wall = BC = ?
Answer
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A ladder of 17m long reaches a wall 15m high.How far is the foot of the ladder from the wall.
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Hint: We should know that the wall is straight and makes an angle of with respect to the ground.That means here a right-angle triangle will be formed.And the given problem will be solved using pythagoras theorem i.e., AC2=AB2+BC2,where AB,BC,AC are the lengths of sides of ΔABC respectively.
Complete answer:
From the problem we have given that,
The length of wall = 15m
The length of the ladder = 17m
As the wall and ground makes an angle , here the ladder will act as a hypotenuse.
Therefore here a right-angled triangle is formed.
Now denote the length of wall = AB=15m
Also the length of ladder = AC =17m
And the distance between the foot of ladder to the wall = BC = ?
Now from the pythagorean principle,
AC2=AB2+BC2⟶equation(1)
And substituting all the values in equation(1) then we get as follows
172=152+BC2
Now,it is simplified as follows
BC2=172−152
BC2=289−225
BC2=64
BC=
√
64
BC=
√
82
BC=8m
Therefore, the distance between the foot of the ladder from the wall is “8m”.
Step-by-step explanation:
I hope it helps you
Answer:
The main answer is 8m
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Step-by-step explanation:
From the problem we have given that,
The length of wall = 15m
The length of the ladder = 17m
As the wall and ground makes an angle , here the ladder will act as a hypotenuse.
Therefore here a right-angled triangle is formed.
Now denote the length of wall = AB=15m
Also the length of ladder = AC =17m
And the distance between the foot of ladder to the wall = BC = ?
Answer
The length of wall = 15m
The length of the ladder = 17m
As the wall and ground makes an angle , here the ladder will act as a hypotenuse.
The lengthfore here a right-angled triangle is formed.
Now denote the length of wall = AB=15m
Also the length of ladder = AC =17m
And the distance between the foot of ladder to the wall = BC = ?
Now from the pythagorean principle,
AC2=AB2+BC2⟶equation(1)
And substituting all the values in equation(1) then we get as follows
172=152+BC2
Now,it is simplified as follows
BC2=172−152BC2=289−225BC2=64
BC=64−−√BC=82−−√BC=8m
Therefore, the distance between the foot of the ladder from the wall is “8m”.