Question

A ladder 17 m long reaches a window 15 m above the ground. Find the distance of the foot of the ladder from the building​

Answer 1

Step-by-step explanation:

The ladder will form a right angled triangle with the wall with hypotenuse 17m and one side 15m. We have to find the third side

Use Pythagoras theorem

17²=15²+x²

x²=17²-15²

x²=298-225

x²=64

x=√64

x=8m

hence, the distance of the foot of the ladder from the building is 8m.

hope the answer is helpful

kindly mark me as a brainliest...

Answer 2

Given :

• A ladder is 17 m long.
• A window is 15 m high from the ground.

To Find :

• Distance of the foot of the ladder from the building.

Solution :

Reference of Figure

$\setlength{\unitlength}{25} \begin{picture}(5,5) \linethickness{1}\put(1,1){\line(1,0){3}} \put(4,1){\line(0,1){4}}\qbezier(1,1)(1,1)(4,5)\put(3.7,1){\line(0,1){0.3}}\put(3.7,1.3){\line(1,0){0.3}}\put(3.9,5.1){ \bf C }\put(3.9,0.5){ \bf B }\put(0.8,0.5){ \bf A }\put(4.1,3){ \bf 15 \: m }\put(1.55,3){ \bf 17 \: m }\put(4.05,4.5){\line(0,1){0.5}}\put(4.1,4.5){\line(0,1){0.5}}\put(3.95,4.5){\line(0,1){0.5}} \end{picture}$

We have ,

• Ladder = AC = 17 m.
• Height of window from the ground = BC = 15 m.
• AB = ?

Using Pythagoras Theorem : AC² = AB² + BC²

$\longrightarrow$ 17² = AB² + 15²

$\longrightarrow$ 17² - 15² = AB²

$\longrightarrow$ 289 - 225 = AB²

$\longrightarrow$ 64 = AB²

$\longrightarrow$ AB = √64

$\longrightarrow$ AB = 8

Hence, the distance of the foot of the ladder from the building = 8 m.