Question

a ladder 17 m long reaches a window of a building 15 m above the ground what is the distance of the foot of the ladder from the wall of the ladder from the wall of the ladder from the wall of the ladder from the wall

Answer 1

hey.
the solution can be found by using Pythagoras rule.
foot= √{(ht)^2-(hypt)^2}.
which is 8 m.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Distance\:between\:wall\:and\:the\:foot\:of\:ladder=20}\:m}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a ladder 17 m long reaches a window of a building 15 m above the ground.

• We have to find Distance between wall and the foot of ladder.

$\green{\underline \bold{Given :}} \\ : \implies \text{Length\:of\: ladder =17\:m} \\ \\ : \implies\text{Heigh\:of\:window=15\:m}\\ \\ \red{\underline \bold{To \: Find:}} \\ : \implies\text{Distance\:between\:wall\:and\:foot\:of\: ladder=?}$

• Accroding to given question :

$\bold{In \: \triangle \: ABC} \\ : \implies {h}^{2} = {p}^{2} + {b}^{2} \: \: \: \: \: \: \: \: \text{(by \: pythagoras \: theorem}) \\ \\ : \implies {17}^{2} = {15}^{2} + {BC}^{2} \\ \\ : \implies (BC)^{2} =289-225\\ \\ : \implies {(BC)}^{2} =64 \\ \\ : \implies BC= \sqrt{64} \\ \\ \green{: \implies \text{BC=8}\:m}$