A ladder 17 m long reaches a window on a wall, which is 8 m above the ground, on
one side of the street. Find the distance of the foot of the ladder from the wall.
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Answer:
Let AC be the ladder, AB be the wall.
Then in △ABC,
= AC² = AB² + BC² (Pythagoras theorem)
= 17² = 15² + BC²
= BC² = 8²
= BC = 8 m
Hence, the foot of the ladder is 8 m from the wall.
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