Question

a ladder 17 M long reaches against a vertical wall the foot of the ladder is 8 M away from base of the Wall The height up to the Wall The ladder with streets

Answer 1

first you draw a triangle according to your question base=8
hypotenuse=17
17^2=8^2+h^2
289=64+h^2
289-64=h^2
225=h^2
h=15

Answer 2

(Refer the above attachment.)
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Hence , By Pythagoras Therom,
${8}^{2} + {x}^{2} = {17}^{2}$
$= \: {x}^{2} = {17}^{2} - {8}^{2}$
$= {x}^{2} = \: 289 - 64 = 225$
$therefore$
$x = \: \sqrt{225}$
So,
$x = \: 15m$

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