Question

A ladder 17m long reaches a window 8 m of above the ground find the distance of the foot of the ladder from base of wall.​

Answer 1

Answer:

The distance of the foot of the ladder from base of wall is 15 m

Answer 2

Given :-

Length of the ladder = 17 m

Height to reach above the ground = 8 m

To Find :-

The distance of the foot of the ladder from base of the wall.

Analysis :-

Using the Pythagoras theorem, find the BC in the formula accordingly in order to find the distance of the foot of the ladder from base of wall.​

Solution :-

(Refer to the attachment for the figure)

Given,

A ladder 10 m long reaches a window 8 m above the ground.

According to the question,

Let BA be the wall and AC be the ladder.

By Pythagoras theorem,

$\underline{\boxed{\sf AC^{2} = AB^{2} + BC^{2}}}$

Substituting their values,

$\sf 10^{2} = 8^{2} + BC^{2}$

$\sf BC^{2} = 100 - 64$

$\sf BC^{2} = 36$

$\sf BC=\sqrt{36}$

$\sf BC=6$

Therefore, the distance of the foot of the ladder from the base of the wall is 6 m