Math, asked by chethubills, 11 months ago

a ladder 17m long reaches a window of a building 15m above the ground the distance of the foot of the ladder from the building​

Answers

Answered by bhavithrarb
3

Answer:

8cm

Step-by-step explanation:

by Pythagoras theorem,

17square-15 square=root64

=8cm

Answered by shhreyaa
4

building is always perpendicular to groupnd

hence, ladder building and ground forms right angled triangle where ladder is hypotenuse.

therefore by Pythagoras theorem,

17 square=15 square +(distance between ladder and building)square

289= 225 + x

therefore x = 8

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