a ladder 17m long reaches a window of a building 15m above the ground the distance of the foot of the ladder from the building
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3
Answer:
8cm
Step-by-step explanation:
by Pythagoras theorem,
17square-15 square=root64
=8cm
Answered by
4
building is always perpendicular to groupnd
hence, ladder building and ground forms right angled triangle where ladder is hypotenuse.
therefore by Pythagoras theorem,
17 square=15 square +(distance between ladder and building)square
289= 225 + x
therefore x = 8
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