A ladder 17m long reaches the window of a building 15m above the ground find the distance of the foot of the ladder from the building
Answers
Answered by
130
The ladder will form a right angled triangle with the wall with hypotenuse 17m and one side 15m. We have to find the third side
Use Pythagoras theorem
[tex] 17^{2}= 15^{2}+x^{2} \\ x^{2} = 17^{2} - 15^{2} = 289-225 = 64 \\ x = \sqrt{64} = 8 m [/tex]
Use Pythagoras theorem
[tex] 17^{2}= 15^{2}+x^{2} \\ x^{2} = 17^{2} - 15^{2} = 289-225 = 64 \\ x = \sqrt{64} = 8 m [/tex]
Answered by
50
See the attach solution for rhe above problem
Attachments:
Similar questions
Computer Science,
8 months ago
Math,
8 months ago
Math,
1 year ago
Math,
1 year ago
English,
1 year ago