A ladder 17m long rests against a vertical wall.The foot of the ladder is 8m away from the base of the wall.How high up the wall will the ladder reach?
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1
Answer:
Hence , By Pythagoras Therom,
{8}^{2} + {x}^{2} = {17}^{2}8
2
+x
2
=17
2
= \: {x}^{2} = {17}^{2} - {8}^{2}=x
2
=17
2
−8
2
= {x}^{2} = \: 289 - 64 = 225=x
2
=289−64=225
thereforetherefore
x = \: \sqrt{225}x=
225
So,
x = \: 15mx=15m
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Answered by
1
Answer:15m
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