Question

A ladder 17m long when set against the wall of a house just reaches window at a height of 15 m from the ground. how far in the lower and of the ladder from the base of wall​

Answer 1

Answer:

let the ladder be ac.

let the wall be ab

and the distance between foot and ladder will be bc.

it forms a right angle, therefore by pythagoras theorem

(ac)²= (ab)²+(bc)²

(17)²= (15)²+(bc)²

289 = 225 + (bc)²

289 - 225 = (bc)²

64= (bc)²

√64= bc

bc = 8

therefore the distance of the base is 8 m.

Step-by-step explanation:

thats the answer.

Answer 2

$\large{\sf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}}{\color{pink}{:}}}}} \tt \: By \: Pythagoras \: theorem \\ \tt \: (ac)²= (ab)²+(bc)² \\ \tt \: (17)²= (15)²+(bc)² \\ \tt \: 289 = 225 + (bc)² \\ \tt \: 289 - 225 = (bc)² \\ \tt \: 64= (bc)² \\ \tt \: √64= bc \\ \tt \: bc = 8m$

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$\sf \: @WildCat7083$