Question

A ladder 19 m long is placed against a wall in such a way that the foot of the ladder is 15 m away from the wall. Find the height of the wall up to which the ladder reaches.​

Answer 1

Answer:

$2 \sqrt{34}$

Step-by-step explanation:

By Pythagoras Theorem

According to the Question

Let the height of the wall to which the ladder reaches be 'x'.

Then,

${19}^{2} = {15}^{2} + {x}^{2} \\ {19}^{2} - {15}^{2} = {x}^{2} \\ \sqrt{ {19}^{2} - {15}^{2} } = x \\ \sqrt{361 - 225} = x \\ x = \sqrt{136} \\ x = 2 \sqrt{34}$