Question

a ladder 2.5 M long is placed against a wall if its foot is 0.7 M away from the wall how high up the wall does it reach

Answer 1

By Pythagoras Theorom,
h^2=b^2+a^2
(2.5)^2= (0.7)^2 + a^2
6.25-0.49=a^2
5.76=a^2
a=2.4cm
Hence, height is 2.4cm

Answer 2

Solutions :-

Given :
A ladder 2.5 m long is placed against a wall
i.e., AC = 2.5 m
Its foot is 0.7 m away from the wall.
i.e., BC = 0.7 m

Find how high up the wall does it reach :-

So, we have to find AB.

By using Pythagoras theorem,

(AB)² + (BC)² = (AC)²
=> (AB)² +(0.7)² = (2.5)²
=> (AB)² + 0.49 = 6.25
=> (AB)² = 6.25 - 0.49
=> (AB)² = 5.76
=> AB = √5.76 = 2.4

Hence,
2.4 m high up the wall does it reach.