A ladder 20 mts high just reaches the top of a wall of height 10 mts then the ladder makes an angle with horizon is
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1
Hi ,
Draw the rough diagram which shows the details of the problem
Diagram shows a right angled triangle ABC . Right angle at
Let the length of ladder AC = 15 m ( hypotenuse )
Angle between ladder and wall < BCA= 60 degrees
Angle between ladder and the ground < CAB = 90 - 60 = 30 degrees
Height of the wall = BC
From triangle ABC,
Sin
Sin 30 = BC / 15
1 / 2 = BC / 15
15 / 2 = BC
7.5 = BC
Therefore,
Height of the wall = BC = 7.5 m
I hope this will useful to you.
*****
Answered by
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TAKE A RIGHT TRIANGLE ABC ,C IS THE RIGHT ANGLE
AB-20
BC-BASE
CA-10
SINB=10/20
=1/2
SINB=SIN30
THEREFORE B=30
30 IS THE REQUIRED ANGLE
PLS MARK AS BRAINLIEST
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