Question

A ladder 25 m long reaches a window if a building 20 m above the ground. Determine the distance of the foot of the ladder

Answer 1

given,height of the building(p)=20cm
length of ledder(h)=25cm
distance between foot of ledder(B)=?

By Pythagoras theorum
h^2=P^2+B^2
25^2=20^2+B^2
625=400+B^2
B^2=625-400
B^2=225
B=root 225
B=15cm

distance between foot of ledder=15cm

Answer 2

Answer:

• Length of BC is 15 m

Step-by-step explanation:

Given

• In ΔABC , ∠C = 90°
• AB = 25 m
• AC = 20 m

To find

• BC

Solution

• AB² = AC² + BC²

(Pythagoras theorem)

• BC² = AB² - AC²
• BC² = 25² - 20²
• BC² = 625 - 400
• BC² = 225
• BC = √225
• BC = 15

∴ BC = 15 m