a ladder 25 m long reaches a window of a building 20 m above the ground. Determine the distance of the foot of ladder from the building
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AB = height of building = 20m
AC = length of ladder = 25m
BC = distance between building and tail of ladder = ?
By Pythagoras theorem,
AC^2 = AB^2 + BC^2
25^2 = 20^2 + BC^2
BC^2 = 625 - 400
= 225
BC = √225
BC = 15m
Therefore, distance between tail of ladder and bottom of building is 15m
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