Question

A ladder 25 m long reaches a window of a building 20 m above the ground. Determine the distance of the foot of the ladder from the building?

Answer 1

Step-by-step explanation:

☯️Given:

• A ladder 25 m reaches a window of a building.
• Building is 20 m above the ground

☯️To Find:

• Distance of the foot of the ladder from the building.

☯️Solution:

25 m ladder = hypotenuse

20 m building = perpendicular

Distance of the foot of the ladder from the building = base

Let the base be x.

✝️ As the pythagoras theorem states that :

p² + b² = h²

ATQ,

→ 20² + x² = 25²

→ 400 + x² = 625

→ x² = 625 - 400

→ x² = 225

→ x = √225

→ x = 15

∴ Distance of the foot of the ladder from the building is 15 m.

Answer 2

Step-by-step explanation:

To Find:

• Distance of the foot of ladder from the building.

Solution:

• Suppose that AB is the ladder, B is the window and CB is the building. Then, Triangle ABC is a right triangle with right-angle C

By Pythagoras Theorem,

⇛ AB² = AC² + BC²

⇛ 25² = AC² + 20²

⇛ AC² = 625 - 400

⇛ AC² = 225

⇛ AC = $\sqrt{225}$

⇛ AC = 15 cm

Hence, the foot of the ladder is at a distance of 15cm from the building.