Question

a ladder 25 m long reaches a window of building 20 m above the ground determine the distance of the foot of the ladder from the building ..​

Answer 1

Answer:

it is forming a right angled triangle.

So, we will use Pythagoras theorem

(h)^2 = (p)^2 + (b)^2

(25)^2 = (20)^2 + (b)^2

625 = 400 + (b)^2

625 - 400 = (b)^2

225 = (b)^2

(15)^2 = (b)^2

15 = b

So, distance of foot of ladder from building is 15 m

Answer 2

Answer :-

Distance of the foot of the ladder from the building = 15 m

Step-by-step explanation :-

Given:

• Ladder height = 25 m
• Height of the window from the ground = 20 m

To find:

Length of base = ?

Solution:

This arrangement is in the form of right angled triangle where:

• Hypotenuse = 25 m
• Height = 20 m
• Base length = x

According to Pythagoras theorem,

(Hypotenuse)² = (Base)² + (Height)²

→ 25² = x² + 20²

⇒ 625 = x² + 400

⇒ 625 - 400 = x²

⇒ x² = 225

⇒ x = √225

⇒ x = ± 15 m

Length can never be negative.

Ignoring the negative sign,

∴ Base length = 15 m