a ladder 25 m long reaches a window of building 20 m above the ground determine the distance of the foot of the ladder from the building ..
Answers
Answered by
1
Answer:
it is forming a right angled triangle.
So, we will use Pythagoras theorem
(h)^2 = (p)^2 + (b)^2
(25)^2 = (20)^2 + (b)^2
625 = 400 + (b)^2
625 - 400 = (b)^2
225 = (b)^2
(15)^2 = (b)^2
15 = b
So, distance of foot of ladder from building is 15 m
Answered by
6
Answer :-
Distance of the foot of the ladder from the building = 15 m
Step-by-step explanation :-
Given:
- Ladder height = 25 m
- Height of the window from the ground = 20 m
To find:
Length of base = ?
Solution:
This arrangement is in the form of right angled triangle where:
- Hypotenuse = 25 m
- Height = 20 m
- Base length = x
According to Pythagoras theorem,
(Hypotenuse)² = (Base)² + (Height)²
→ 25² = x² + 20²
⇒ 625 = x² + 400
⇒ 625 - 400 = x²
⇒ x² = 225
⇒ x = √225
⇒ x = ± 15 m
Length can never be negative.
Ignoring the negative sign,
∴ Base length = 15 m
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