Math, asked by gokuSSGSSmay, 2 months ago

a ladder 25m long is placed is a slanting position against a wall such that it touches the wall at 20m above the ground. How far is the foot of the ladder from the bottom of the wall?​

Answers

Answered by SattwikRay
6

Answer:

Given length of the ladder in a slanting position = 25m

Given length of the wall = 20m

Length between the foot of the ladder and the foot of the wall = ?

Now, if we try to imagine the figure, the ladder is the hypotenuse, the wall is the height and the distance between the foot of the ladder and the foot of the wall is the base which turns this figure into a right angled triangle, isn't. In these type of questions, you just have to use your imagination and put the formulas that is suitable! It's simple AF!

So, let's assume that the the triangle is named ΔABC

So, the length of the ladder (hypotenuse) = AC

Height of the wall (height) = AB

Length between the foot of the ladder and the wall (base) = BC

So, as per question, we can find the length between the ladder and the wall by applying Pythagoras Theorem!

⇒ Hypotenuse² = Base² + Height²

⇒ AC² = BC² + AB²

⇒ 25² = BC² + 20²

⇒ 625 = BC² + 400

⇒ 625 - 400 = BC²

⇒ 225 = BC²

\sqrt{225} = BC

⇒ 15m = BC

There you go!

The length of BC is 15m which means the length between the foot of the ladder and the foot of the wall is 15m!

Thnx and have a nice day!

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