Question

A ladder 25m long reaches a window of a building 20m above a ground​

Answer 1

Answer:

then what we have to do in this

Answer 2

Length of ladder = 25 m

A ladder reaches a window of a building 20 m above the ground.

Refer the attached figure

AB = 20

AC = 25

We are supposed to find the distance of the foot of the ladder from the building i.e. BC

Hypotenuse^2=Perpendicular^2+Base^2Hypotenuse

2

=Perpendicular

2

+Base

2

AC^2=AB^2+BC^2AC

2

=AB

2

+BC

2

25^2=20^2+BC^225

2

=20

2

+BC

2

\sqrt{25^2-20^2}=BC

25

2

−20

2

=BC

15=BC15=BC

Hence the distance of the foot of the ladder from the building is 15 m