A ladder 25m long reaches a window of building 20 m above the ground...Determine the distance of the foot of yhe ladder from the building....
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length of ladder =25 m
length of buliding =20 m
therefore the length from the foot of ladder to buliding= x
20²+x²=25² { phythagors theoram }
x²=625-400
x²=225
x=15 m
length of buliding =20 m
therefore the length from the foot of ladder to buliding= x
20²+x²=25² { phythagors theoram }
x²=625-400
x²=225
x=15 m
Answered by
4
hii mate here is the answer to your question
length of the ladder is 25 m .
length of the building is 20 m.
let us assume that the length of the foot of the ladder from the building as x .
therefore by applying pythagoras theorem, we get
20^2+x^2=25^2
---->>x^2=625-400=225
---->>x=sq.rt under 225=15.
therefore the distance of the foot of the ladder from the building is 15 m .
hope this helps
keep smiling
length of the ladder is 25 m .
length of the building is 20 m.
let us assume that the length of the foot of the ladder from the building as x .
therefore by applying pythagoras theorem, we get
20^2+x^2=25^2
---->>x^2=625-400=225
---->>x=sq.rt under 225=15.
therefore the distance of the foot of the ladder from the building is 15 m .
hope this helps
keep smiling
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